A Bag Contains 6 Red Marbles 4 Blue Marbles

You have 8 6 4 18 marbles each assumed to have a 1 18 probability of being drawn.

A bag contains 6 red marbles 4 blue marbles.

A marble is drawn from the bag and is not replaced. The problem asks for the probability of rr or bb. What is the probability that both marbles drawn were red. Find p red or blue.

A bag contains 6 red marbles 4 blue marbles 7 green marbles and 3 yellow marbles. There are 8 6 48 ways of drawing blue then red so p 8 6 18 18 4 3 9 9 4 3 9 4 27 0 148148148 or just under 15. If a marble is randomly selected from the bag what is the probability that it is blue. There would be a 7 19 or 36 84.

A bag contains 6 red marbles 6 white marbles and 4 blue. You draw 4 marbles out at random without replacement. A bag contains 6 red marbles 7 blue marbles and 6 green marbles if one marble is randomly picked from the bag what is the probability that this is a blue marble. Given that you have bb.

Favorite answer 6 4 6 6 4 10 16. Total number of marbles in the bag is 3 4 7. How do u do it. Work out the probability that the two marbles taken from the bag are the same color.

P both are red 4 10 3 9 12 90 p both are blue 6 10 5 9 30 90 p both are of the same color 42 90. A bag contains 3 red marbles and 4 blue marbles. Asked 01 09 17 a bag contains 4 red marbles and 5 blue marbles whats probability of randomly selecting a blue marble and then without replacing it selecting a red marble. A marble is taken at random and replaced.

Then a second marble is drawn.